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x^2-4.5x+1=0
a = 1; b = -4.5; c = +1;
Δ = b2-4ac
Δ = -4.52-4·1·1
Δ = 16.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{16.25}}{2*1}=\frac{4.5-\sqrt{16.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{16.25}}{2*1}=\frac{4.5+\sqrt{16.25}}{2} $
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